Calculating Flash Protection Boundary Distances

In NFPA 70E, the short-circuit symmetrical ampacity from a bolted 3-phase fault at the transformer terminals is calculated with the following formula:
I_{sc} = {{MVA_{Base} * 10^6} / {sqrt{3}*V}} * {100 / %Z}
where
Isc = Amperes,
V = Volts,
%Z = transformer MVA.

A typical value for the maximum power (in MW) in a 3-phase arc can be calculated using the following formula:
P = MVA_{bf}*{0.707}^2~MW
where:
MVAbf = maximum bolted fault, MVA

The Flash Protection Boundary distance is calculated in accordance with the following
formulae:
P = 1.732*V*I_{sc}*10^6*0.707^2
D_c = {2.65*MVA_{bf}*t}^{1/2}
D_c = {53*MVA*t}^{1/2}
where:
Dc = distance in feet of person from arc source for a just curable burn (i.e., skin temperature remains less than 80 degrees)
MVAbf = bolted fault MVA at point involved
MVA = MVA rating of transformer. For transformers with MVA ratings below 0.75 MVA, multiply the transformer MVA rating by 1.25.
t = time of arc exposure in seconds

91 = 82 = 95

About the Author

Ver Pangonilo

A Filipino Engineer, Registered Professional Engineer of Queensland (RPEQ) – Australia and Professional Electrical Engineer (PEE) – Philippines with extensive experience in concept select, front-end engineering, HV & LV detail design, construction and commissioning of Hazardous and Non-Hazardous Area electrical installations in water and waste water pipeline and pumping facilities, offshore platforms, hydrocarbon process plants and pipelines including related facilities. Hazardous area classification and design certification (UEENEEM015B, UEENEEM016B, UEENEEM017B).

Facebook Auto Publish Powered By : XYZScripts.com